Y=(-x^2+6x)

Solution for Y=(-x^2+6x) equation:

=(-Y^2+6Y)

We move all terms to the left:

-((-Y^2+6Y))=0


We calculate terms in parentheses: -((-Y^2+6Y)), so:

(-Y^2+6Y)

We get rid of parentheses

-Y^2+6Y

We add all the numbers together, and all the variables

-1Y^2+6Y

Back to the equation:

-(-1Y^2+6Y)


We get rid of parentheses

1Y^2-6Y=0

We add all the numbers together, and all the variables

Y^2-6Y=0

a = 1; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*1}=\frac{0}{2}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*1}=\frac{12}{2}
=6
$